0=-0.017x^2+1.16x+5.7

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Solution for 0=-0.017x^2+1.16x+5.7 equation:



0=-0.017x^2+1.16x+5.7
We move all terms to the left:
0-(-0.017x^2+1.16x+5.7)=0
We add all the numbers together, and all the variables
-(-0.017x^2+1.16x+5.7)=0
We get rid of parentheses
0.017x^2-1.16x-5.7=0
a = 0.017; b = -1.16; c = -5.7;
Δ = b2-4ac
Δ = -1.162-4·0.017·(-5.7)
Δ = 1.7332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.16)-\sqrt{1.7332}}{2*0.017}=\frac{1.16-\sqrt{1.7332}}{0.034} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.16)+\sqrt{1.7332}}{2*0.017}=\frac{1.16+\sqrt{1.7332}}{0.034} $

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